Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship

Published: 29/05/2017
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship
Source: GMATCLUB.COM

Let them meet 'n' hours after 4 pm. From 1 to 4 pm, ship A has already travelled = 15*3 = 45 miles So in 'n' hours, A has total travelled = (45 + 15n) miles and B has travelled = 25n miles Since they meet at that time, distances should be equal OR 45+15n = 25n Solving we get n=4.5 So the ships meet 4.5 hours after 4 pm, OR at 8.30 pm Option A is the answer

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